How do you solve #4( 8+ 2x ) - 6( x + 3) = - 5x + 6x#?

1 Answer
Jun 7, 2018

#x = -14#

Explanation:

#4(8+2x) - 6(x+3) = -5x + 6x#

First, combine #-5x + 6x#:
#4(8+2x) - 6(x+3) = x#

Now use the distributive property (shown below) to expand/simplify #4(8+2x)# and #-6(x+3)#:
cdn.virtualnerd.com

Following this image, we know that:
#color(blue)(4(8+2x) = (4 * 8) + (4 * 2x) = 32 + 8x)#
and
#color(blue)(-6(x+3) = (-6 * x) + (-6 * 3) = -6x - 18)#

Put them back into the equation:
#32 + 8x - 6x - 18 = x#

Combine like terms on the left side:
#14 + 2x = x#

Subtract #color(blue)(2x)# from both sides:
#14 + 2x quadcolor(blue)(-quad2x) = x quadcolor(blue)(-quad2x)#

#14 = -x#

Divide both sides by #color(blue)(-1)#:
#14/color(blue)(-1) = (-x)/color(blue)(-1)#

#-14 = x#

Therefore, #x = -14#.

Hope this helps!