# How do you solve 4( e ^ { x } + 1) = 12?

Then teach the underlying concepts
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#### Explanation

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1
Jim G. Share
Mar 8, 2018

$x = \ln 2$

#### Explanation:

$\text{divide both sides by 4}$

$\Rightarrow {e}^{x} + 1 = 3$

$\Rightarrow {e}^{x} = 3 - 1 = 2$

•color(white)(x)[logx^nhArrnlogx" and "lne^x=x]

$\text{take ln of both sides}$

$\ln {e}^{x} = \ln 2$

$\Rightarrow x = \ln 2$

Then teach the underlying concepts
Don't copy without citing sources
preview
?

#### Explanation

Explain in detail...

#### Explanation:

I want someone to double check my answer

1
Mar 8, 2018

$x = 0.693$, to three d.p.

#### Explanation:

We have $4 \left({e}^{x} + 1\right) = 12$

So:

${e}^{x} + 1 = 3$

${e}^{x} = 2$

$\ln {e}^{x} = \ln 2$

$x \ln e = \ln 2$

$x = \ln 2$

$x = 0.693$

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