# How do you solve #4( e ^ { x } + 1) = 12#?

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Jim G.
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Mar 8, 2018

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#"divide both sides by 4"#

#rArre^x+1=3#

#rArre^x=3-1=2#

#•color(white)(x)[logx^nhArrnlogx" and "lne^x=x]#

#"take ln of both sides"#

#lne^x=ln2#

#rArrx=ln2#

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Surya K.
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Mar 8, 2018

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We have

So:

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