Question

How do you solve `4(k+2)=3`?

Answer 1

`k=-5/4`

Explanation:

distribute the bracket.

`rArr4k+8=3`

subtract 8 from both sides of the equation.

`4xcancel(+8)cancel(-8)=3-8`

`rArr4x=-5`

To solve for x, divide both sides by 4

`(cancel(4) x)/cancel(4)=(-5)/4`

`rArrx=-5/4`

`color(blue)"As a check"`

Substitute this value for x into the left side of the equation and if it is equal to the right side then it is a solution.

`x=-5/4to4(-5/4+2)=-5+8=3=" right side"`

`rArrx=-5/4" is the solution"`