# How do you solve 4(l-1)+2(l+1)=0?

Jun 30, 2015

Distribute the $4$ and $2$, group like terms, then solve for $l$.

#### Explanation:

$4 \left(l - 1\right) + 2 \left(l + 1\right) = 0$

Distribute the $4$ and $2$.

$4 l - 4 + 2 l + 2 = 0$

Group like terms.

$4 l + 2 l - 4 + 2 = 0$

$6 l - 2 = 0$

Add $2$ to both sides.

$6 l = 2$

Divide both sides by $6$.

$l = \frac{2}{6}$

Simplify.

$l = \frac{1}{3}$