# How do you solve 4 log x - log x = 64?

Dec 21, 2015

$x = {10}^{\frac{64}{3}}$

#### Explanation:

$4 \log x - \log x = 64$

$3 \log x = 64$

$\log x = \frac{64}{3}$

Recall that $\log x = {\log}_{10} x$.

Exponentiate both sides to undo the logarithm.

${10}^{{\log}_{10} x} = {10}^{\frac{64}{3}}$

$x = {10}^{\frac{64}{3}}$

$x \approx 2.1544 \times {10}^{21}$