How do you solve #4(u+1) + u =8(u-1)+6#?

1 Answer
Jan 15, 2018

#u = 2#

Explanation:

#4(u+1) + u = 8(u-1) + 6#

First, let's use the distributive property to simplify #4(u+1)# and #8(u-1)#:
#4u + 4 + u = 8u - 8 + 6#

Now let's simplify each side by combining "like-terms":
#5u + 4 = 8u - 2#

Now put the variables on the left side of the equation and the numbers on the right:
#-3u = -6#

Now we divide both sides of the equation by -3:
#u = 2#