How do you solve #-4(x-1)<12#?

2 Answers
Jul 10, 2016

Answer:

#x > -2#

Explanation:

Remember when dividing/multiplying a negative number when dealing with inequalities, the symbol must be switched.

#-4(x-1)<12#

Divide out the #-4#.

#(x-1) > -3#

Use additive inverse to get #x# by itself (add #1#).

#x > -2#

We found that #x# is a solution when it accounts for all values greater than #-2#.

Jul 10, 2016

Answer:

#x > -2#

Explanation:

#-4*(x-1) < 12#

# 4*x-4 > -12#

#4*x > -8#

#x > -2#

graph{x> -2 [-10, 10, -5, 5]}