How do you solve $4^(x+2)=48$ ?

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Answer 1 · 2016-10-27T20:25:44

$x~~0.7925$

$4^(x+2) = 48$

$ln 4^(x+2) = ln 48$

$(x+2) ln 4 = ln 48$

$x+2=ln 48/ln 4$

$x=ln 48/ln 4-2$

$x~~0.7925$

How do you solve 4^(x+2)=484^(x+2)=48?