How do you solve #4 (X - 3) ^2 = 324#? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer Ratnaker Mehta Aug 18, 2016 #X=12, or,-6#. Explanation: #4(X-3)^2=324#. #:. (X-3)^2=324/4=81#. #:. X-3=sqrt81=+-9#. #:. X=3+-9#. #:. X=3+9=12, or, X=3-9=-6#. These roots satisfy the given eqn. Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 1235 views around the world You can reuse this answer Creative Commons License