Question

How do you solve `4( x + 3) - 3a x = 25+ 3a` in terms of `a`?

Answer 1

`x = (13+3a)/(4-3a)`

Explanation:

'In terms of `a`' means there will be `a` in the answer, we cannot find just a number answer.

`4(x+3) -3ax = 25+3a" "larr` remove brackets

`4x+12 -3ax = 25+3a`

`4x-3ax = 25+3a-12larr` arrange with `x` terms on one side

`x(4-3a) = 13+3a" "larr` factorise to get `x` as a single factor

`x = (13+3a)/(4-3a)" "larr` solve for `x`