How do you solve 4^x-3=5? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Gerardina C. Jul 20, 2016 x=3/2 Explanation: First let's have the equivalent equation 4^x=8 Then, since 4=2^2 and 8=2^3, let's substitute: 2^(2x)=2^3 so 2x=3 x=3/2 Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve 9^(x-4)=81? How do you solve logx+log(x+15)=2? How do you solve the equation 2 log4(x + 7)-log4(16) = 2? How do you solve 2 log x^4 = 16? How do you solve 2+log_3(2x+5)-log_3x=4? See all questions in Logarithmic Models Impact of this question 1086 views around the world You can reuse this answer Creative Commons License