How do you solve #4(x-3)>9(x+1)#?

1 Answer
Nov 26, 2016

Answer:

#x<-21/5#

Explanation:

distribute brackets on both sides of the inequality.

#4x-12>9x+9#

Collect terms in x on one side and numerical values on the other.

subtract 4x from both sides.

#cancel(4x)cancel(-4x)-12>9x-4x+9#

#rArr-12>5x+9#

subtract 9 from both sides.

#-12-9>5xcancel(+9)cancel(-9)#

#rArr-21>5x#

To solve for x, divide both sides by 5

#(-21)/5>(cancel(5) x)/cancel(5)#

#rArr-21/5>xrArrx<-21/5#