# How do you solve 4(x-3)>9(x+1)?

Nov 26, 2016

$x < - \frac{21}{5}$

#### Explanation:

distribute brackets on both sides of the inequality.

$4 x - 12 > 9 x + 9$

Collect terms in x on one side and numerical values on the other.

subtract 4x from both sides.

$\cancel{4 x} \cancel{- 4 x} - 12 > 9 x - 4 x + 9$

$\Rightarrow - 12 > 5 x + 9$

subtract 9 from both sides.

$- 12 - 9 > 5 x \cancel{+ 9} \cancel{- 9}$

$\Rightarrow - 21 > 5 x$

To solve for x, divide both sides by 5

$\frac{- 21}{5} > \frac{\cancel{5} x}{\cancel{5}}$

$\Rightarrow - \frac{21}{5} > x \Rightarrow x < - \frac{21}{5}$