How do you solve 4( x + 4) \geq 3( x + 5) + x4(x+4)3(x+5)+x?

1 Answer
Jun 24, 2017

16>=151615, which is always true, therefore there are an infinite number of values for xx.

Explanation:

Solve:

4(x+4)>=3(x+5)+x4(x+4)3(x+5)+x

Expand both sides.

4x+16>=3x+15+x4x+163x+15+x

Simplify.

4x+16>=4x+154x+164x+15

Cancel the 4x4x on both sides.

color(red)cancel(color(black)(4x))+16>=color(red)cancel(color(black)(4x))+15

16>=15

Because this inequality is always true, there are an infinite number of values for x