How do you solve #4/(x-8)>0#?

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Answer 1 · 2017-01-07T06:40:19

The answer is #x in ] 8,+oo[ #

We solve this equation with a sign chart

Let #f(x)=4/(x-8)#

#color(white)(aaaa)##x##color(white)(aaaaaa)##-oo##color(white)(aaaaaa)##8##color(white)(aaaaaa)##+oo#

#color(white)(aaaa)##x-8##color(white)(aaaaaaa)##-##color(white)(aaaaaa)##+#

#color(white)(aaaa)##f(x)##color(white)(aaaaaaaaa)##-##color(white)(aaaaaa)##+#

Therefore,

#f(x)>0#, when #x in ] 8,+oo[ #