# How do you solve 4(y - 2) = 3(y + 1) + 1 - 3y?

Jan 1, 2016

color(blue)(y=3

#### Explanation:

$4 \left(y - 2\right) = 3 \left(y + 1\right) + 1 - 3 y$

$4 \times \left(y\right) + 4 \times \left(- 2\right) = 3 \times \left(y\right) + 3 \times \left(1\right) + 1 - 3 y$

$4 y - 8 = 3 y + 3 + 1 - 3 y$

$4 y - 8 = 3 y + 4 - 3 y$

$4 y - 8 - 4 = 3 y - 3 y$

$4 y - 12 = 0$

$4 y = 12$

$y = \frac{12}{4}$

color(blue)(y=3