How do you solve #-41- 3x = 37- 9x#?

Question

695 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-13T18:58:38

See the entire solution process below:

First, add #color(red)(41)# and #color(blue)(9x)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#color(red)(41) - 41 - 3x + color(blue)(9x) = color(red)(41) + 37 - 9x + color(blue)(9x)#

#0 + (-3 + color(blue)(9))x = 78 - 0#

#6x = 78#

Now, divide each side of the equation by #color(red)(6)# to solve for #x# while keeping the equation balanced:

#(6x)/color(red)(6) = 78/color(red)(6)#

#(color(red)(cancel(color(black)(6)))x)/cancel(color(red)(6)) = 13#

#x = 13#