How do you solve #4b+6=2-b+4#?

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Answer 1 · 2017-01-16T14:08:17

See the entire solution process below:

FIrst, combine like terms on the right side of the equation:

#4b + 6 = 2 + 4 - b#

#4b + 6 = 6 - b#

Next, add and subtract the necessary terms from each side of the equation to isolate the #b# terms while keeping the equation balanced:

#4b + 6 - color(red)(6) + color(blue)(b) = 6 - b - color(red)(6) + color(blue)(b)#

#4b + color(blue)(b) + 6 - color(red)(6) = 6 - color(red)(6) - b + color(blue)(b)#

#5b + 0 = 0 - 0#

#5b = 0#

Now, divide each side of the equation by #color(red)(5)# to solve for #b# while keeping the equation balanced:

#(5b)/color(red)(5) = 0/color(red)(5)#

#(color(red)(cancel(color(black)(5)))b)/cancel(color(red)(5)) = 0#

#b = 0#