How do you solve #-4c-1.2=0.8#?

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Answer 1 · 2017-04-27T06:21:24

#c=-0.5#

#-4c-1.2=0.8#

or

#-4c=1.2+0.8#

or

#-4c=2#

or

#4c=-2#

or

#c=-2/4#

or

#c=-1/2#

or

#c=-0.5#

Answer 2 · 2017-04-27T06:52:13

#c=-1/2=-0.5#

#-4c-1.2=0.8# original

Add 1.2 to both sides...
#-4c\cancel(-1.2)\cancel(\color(red)(+1.2))=0.8\color(red)(+1.2)#
Simplify... #-4c=0.8+1.2#
which becomes #-4c=2.0# otherwise known as #-4c=2#
Divide both sides by -4...
#(\cancel(-4)c)/(\cancel(\color(red)(-4)))=2/\color(red)(-4)# also written as #c=-2/4#
Simplifying the resulting fraction... #c=-2/4\rarr-(1\cdot2)/(2\cdot2)#
you can remove a 2 from the numerator and denominator... so your result is

#c=-1/2#, or if you want it in decimal form, #c=-0.5#