# How do you solve 4c-4<8c-16<6c-6?

Jun 28, 2018

$3 < c < 5$

#### Explanation:

$4 c - 4 < 8 c - 16 < 6 c - 6$

separate into two inequalities:

$4 c - 4 < 8 c - 16$
$8 c - 16 < 6 c - 6$

solving $4 c - 4 < 8 c - 16$:

$- 4 < 4 c - 16$

$12 < 4 c$

$3 < c$

solving $8 c - 16 < 6 c - 6$:

$8 c < 6 c + 10$

$2 c < 10$

$c < 5$

now we have $3 < c$ and $c < 5$

giving $3 < c < 5$.