How do you solve #4e ^ { 7x } = 10,273#?

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Answer 1 · 2016-12-23T16:46:42

I have taken you to a point where you should be able to finish it.

Note that #" "ln(e)=1#

Taking logs of both sides

#ln(4e^(7x))=ln(10237)#

#7xln(4e)=ln(10237)#

#7x(ln(4)+ln(e))=ln(10237)#

#7x=(ln(10237))/(ln(4)+1)#

#x=(ln(10237))/(7ln(4)+1)#

I will let you finish this off!