How do you solve #4p^2=-25p-25# using the quadratic formula?

1 Answer
Apr 11, 2018

Answer:

#-5 or (-5)/4#

Explanation:

To use the quadratic formula our function has to be in the form:

#a^2 + bx +c =0#

So, let's start off by subtracting #4p^2# from both sides, to get it into that form. That gives us:

#0 = -4p^2 -25p - 25#

I'm also going to multiply both sides by #-1#, to eliminate all of the negatives. You don't have to do this, but it will make the process quite a bit cleaner. That leaves us with:

#0 = 4p^2 +25p + 25#

So, #a = 4#, #b=25#, #c=25#

Now we simply substitute our values into the quadratic equation

= #(-b+-sqrt(b^2-4ac))/(2a)#

= #(-(25)+-sqrt((25)^2-4(4)(25)))/(2(4))#

= #(-25+-sqrt(225))/(8)#

= #(-25+-15)/(8)#

= #(-40)/(8) or (-10)/8#

= #-5 or (-5)/4#