Question

How do you solve `4p^2=-7p-3` using the quadratic formula?

Answer 1

See Explanation

Explanation:

To solve, you must first move all the terms to one side, so: `4p^2+7p+3=0`. Then, the quadratic formula is `x=\frac {-b\pm \sqrt {b^{2}-4ac}}(2a)`. Plug in 4 for a, 7 for b and 3 for c. You get `x=\frac {-7\pm \sqrt {7^{2}-4*4*3}}(2*4)=\frac {-7\pm 1}(8)` so, `x=(-7+1)/(8)=-6/8=-3/4` and `x=(-7-1)/(8)=(-8)/8=-1`. x=-1 and -3/4