How do you solve #4x-1/6=3#?

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Answer 1 · 2017-04-08T03:53:31

#x=19/24#

As #4x-1/6=3#, adding #1/6# on both sides we get

#4x-1/6+1/6=3+1/6#

or #4x=19/6#

Dividing each side by #4#, we get

#x = 19/6 ×1/4=19/24#

Answer 2 · 2017-04-08T03:54:20

#x = 19/24#

First, put constant terms together.
#4x = 3 + 1/6#
#4x = 19/6#

Divide both sides by 4 so that you get #x# on its own

#x = 19/24#

Answer 3 · 2017-04-08T03:56:10

Multiply by the Least Common Denominator and solve for x.

#x = 19/24#

The LCM is 6. so multiplying by 6 gives

# 6 xx 4x - 6 xx 1/6 = 6 xx 3#

Doing the math gives:

# 24x - 1 = 18#

add + 1 to both sides

# 24x -1 +1 = 18 +1 #

This results in

# 24 x = 19 #

divide both sides by 24

# (24x)/24 = 19/24#

This gives the awkward value of

# x = 19/24#

To check, substitute # x = 19/24# into the #given# equation:

#4x - 1/6 = 3#

#cancel(4)(19/cancel(24)) - 1/6 = 3#

#(19/6) - 1/6 = 18/6 =3#