Two ways:
1.
4x−2(1−x)=2(3x−2) factor out 2
2(2x−(1−x))=2(3x−2) divide by 2
2x−1+x=3x−2 simplify
3x−1=3x−2 + 1 to both sides (by this point we can see it is a contradiction)
3x=3x−1 divide by 3
x≠x−(13) impossible / false statment
2.
4x−2(1−x)=2(3x−2) expand brackets
4x−2+2x=6x−4 combine like terms (simplify)
6x−2=6x−4 divide by 2 (by this point we can see it is a contradiction)
3x−1=3x−2 + 1
3x=3x−1 divide by 3
x≠x−(13) impossible / false statment
In both ways we see a statement which is false . You can never have x=x−(13) or any similar statement - it's like saying 1 = 1 - (1/3). It is just not true. Therefore the original statement is a contradiction and cannot be solved.
