# How do you solve 4x^2= 16 using the quadratic formula?

May 15, 2018

$x = 2 \mathmr{and} x = - 2$
$4 {x}^{2} = 16$
${x}^{2} = 4$
$x = \pm 2$

#### Explanation:

Rearrange

$4 {x}^{2} + 0 x - 16 = 0$

a=4, b=0, c=-16 substitute these values into the formula.