Question

How do you solve `4x ^ { 2} - 25x + 36= 0`?

Answer 1

`x_1=9/4` and `x_2=4`

Explanation:

`4x^2-25x+36=0`

`4x^2-16x-9x+36=0`

`4x*(x-4)-9*(x-4)=0`

`(4x-9)*(x-4)=0`

So, `x_1=9/4` and `x_2=4`