Question

How do you solve `4x^2 - 2x - 1 = 0`?

Answer 1

Solve `y = 4x^2 - 2x - 1 = 0`

Ans: `1/4 +- sqrt5/4`

Explanation:

Use the quadratic formula
`D = d^2 = b^2 - 4ac = 4 + 16 = 20 -> d = +- 2sqrt5`

`y = 2/8 +- (2sqrt5)/8 = 1/4 +- sqrt5/4`