How do you solve #4x^2=3x#? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer Tony B Nov 23, 2015 #x=0 ; color(white)(...) x=3/4# Explanation: Given: #4x^2=3x# So #color(white)(.....)4x^2-3x=0# #color(white)(..,,...)x(4x-3)=0# In which case #x=0 or 4x-3=0# Consider #4x-3=0 -> 4x=3# So #x=3/4# Solution: #x=0 ; color(white)(...) x=3/4# Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 2272 views around the world You can reuse this answer Creative Commons License