# How do you solve #4x^2 + 4x + 1 > 0#?

##### 2 Answers

#### Explanation:

Firstly, We have to solve the related second degree equation:

We could use the well-known formule:

So we have:

having a double root from the related equation, the solution must be:

You need to take a look at the number of real roots this polynomial has.

#### Explanation:

In order to know where this polynomial is positive and negative, we need its roots. We will of course use the quadratic formula in order to find them.

The quadratic formula gives you the expression of the roots of a trinomial

This root is

graph{4x^2 + 4x + 1 [-2.234, 2.092, -0.276, 1.887]}