How do you solve # |4x-2|=6#?

1 Answer
Apr 9, 2016

Answer:

#x=-1,2#

Explanation:

The procedure is to separate the equation in two branches:

#1) if 4x-2>0:#

#|4x-2|=6 and 4x-2>0#

#4x-2=6 and 4x>2#

#4x=6+2 and x>2/4#

#x=8/4 and x>2/4#

#x=2 and x>1/2#

#x=2#


#2) if 4x-2<0:#

#|4x-2|=6 and 4x-2<0#

#-4x+2=6 and 4x<2#

#-4x=6-2 and x<2/4#

#x=-4/4 and x<2/4#

#x=-1 and x<1/2#

#x=-1#