# How do you solve 4x^2 + 6x + 2 = 0?

Jun 27, 2015

$x = - \frac{1}{2}$ or $x = - 1$

#### Explanation:

Given $4 {x}^{2} + 6 x + 2 = 0$
We can simplify this by dividing both sides by 2
$\textcolor{w h i t e}{\text{XXXX}}$$2 {x}^{2} + 3 x + 1 = 0$
The left side can be factored fairly simply as
$\textcolor{w h i t e}{\text{XXXX}}$$\left(2 x + 1\right) \left(x + 1\right) = 0$
Which implies either $\left(2 x + 1\right) = 0$
or $\left(x + 1\right) = 0$
That is either $x = - \frac{1}{2}$
or $x = - 1$