# How do you solve 4x^2=9x?

May 28, 2016

$x = 0 , \frac{9}{4}$

#### Explanation:

$4 {x}^{2} = 9 x$
$4 {x}^{2} - 9 x = 0$
$x \left(4 x - 9\right) = 0$
$x = 0$
$4 x - 9 = 0$
$4 x = 9$
$x = \frac{9}{4}$

Aug 10, 2018

$x = 0$ and $x = \frac{9}{4}$

#### Explanation:

We have a second degree term, so this is beginning to look like a quadratic. Let's subtract $9 x$ from both sides to get

$4 {x}^{2} - 9 x = 0$

Both terms have an $x$ in them, so we can factor that out to get

$x \left(4 x - 9\right) = 0$

Setting both factors equal to zero, we get

$x = 0$ and $x = \frac{9}{4}$

Hope this helps!