How do you solve #4x - 22< - 2( x + 2)#?

1 Answer
Mar 27, 2017

#x<3#

Explanation:

Solve:

#4x-22<-2(x+2)#

Expand.

#4x-22<-2x-4#

Add #2x# to both sides.

#2x+4x-22<-2x-4+2x#

Simplify.

#6x-22<-color(red)cancel(color(black)(2x))-4+color(red)cancel(color(black)(2x)#

#6x-22<-4#

Add #22# to both sides.

#22+6x-22<-4+22#

Simplify.

#color(red)cancel(color(black)(22))+6x-color(red)cancel(color(black)(22))<-4+22#

#6x<18#

Divide both sides by #6#.

#(6x)/6<18/6#

Simplify.

#x<3#