# How do you solve [(4x-3, 3y), (7,13)]=[(9,-15), (7,2z+1)]?

Jan 28, 2017

We get that:
$x = 3$
$y = - 5$
$z = 6$

#### Explanation:

Fot the two matrices to be equal each corresponding element must be equal.
So we need that:

$4 x - 3 = 9$
$3 y = - 15$
$7 = 7$
$13 = 2 z + 1$

from these equations we see that the third is ok while for the others (rearranging):

$x = \frac{12}{4} = 3$
$y = - \frac{15}{3} = - 5$
$z = \frac{12}{2} = 6$