How do you solve #4x - 3= 4( x - 1) + 6#?

1 Answer
Jim G.
Dec 13, 2016

#"no solution"#

Explanation:

First distribute the bracket on the right side of the equation.

#rArr4x-3=4x-4+6#

collect terms in x on the left and numeric values on the right.

subtract 4x from both sides.

#cancel(4x)cancel(-4x)-3=cancel(4x)cancel(-4x)+2#

#rArr-3=2larr" FALSE"#

#"Hence the equation has no solution"#

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