# How do you solve -4x+3<=-5+11?

Jul 25, 2018

$x \ge - \frac{3}{4}$

#### Explanation:

$- 4 x + 3 \le - 5 + 11$

Simplify the right side:
$- 4 x + 3 \le 6$

Add $\textcolor{b l u e}{4 x}$ to both sides:
$- 4 x + 3 \quad \textcolor{b l u e}{+ \quad 4 x} \le 6 \quad \textcolor{b l u e}{+ \quad 4 x}$

$3 \le 6 + 4 x$

Subtract $\textcolor{b l u e}{6}$ from both sides:
$3 \quad \textcolor{b l u e}{- \quad 6} \le 6 + 4 x \quad \textcolor{b l u e}{- \quad 6}$

$- 3 \le 4 x$

Divide both sides by $\textcolor{b l u e}{4}$:
$\frac{- 3}{\textcolor{b l u e}{4}} \le \frac{4 x}{\textcolor{b l u e}{4}}$

$- \frac{3}{4} \le x$

Therefore,
$x \ge - \frac{3}{4}$

Hope this helps!