How do you solve #4x + 3 <55#?

1 Answer
Jun 29, 2016

Answer:

#x<13#

Explanation:

#color(blue)("General comment")#
Treat like a normal equation. The only thing to watch for is if you multiply an inequality by #(-1)#. This turns the sign round the other way. You do not have any need for multiplying by -1 in this question so it is not an issue.
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#color(blue)("Answering your question")#

Given:#" "4x+3<55#

Subtract 3 from both sides

#4x<52#

Divide both sides by 4

#4/4xx x<52/4#

But #4/4=1" and "52/4=13#

#1xx x<13#

#x<13#