# How do you solve 4x + 3 <55?

Jun 29, 2016

$x < 13$

#### Explanation:

$\textcolor{b l u e}{\text{General comment}}$
Treat like a normal equation. The only thing to watch for is if you multiply an inequality by $\left(- 1\right)$. This turns the sign round the other way. You do not have any need for multiplying by -1 in this question so it is not an issue.
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$\textcolor{b l u e}{\text{Answering your question}}$

Given:$\text{ } 4 x + 3 < 55$

Subtract 3 from both sides

$4 x < 52$

Divide both sides by 4

$\frac{4}{4} \times x < \frac{52}{4}$

But $\frac{4}{4} = 1 \text{ and } \frac{52}{4} = 13$

$1 \times x < 13$

$x < 13$