How do you solve #4x - 5+ 7x > 72#?

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Answer 1 · 2018-01-15T23:31:29

See a solution process below:

First, group and combine like terms on the left side of the inequality:

#4x - 5 + 7x > 72#

#4x + 7x - 5 > 72#

#(4 + 7)x - 5 > 72#

#11x - 5 > 72#

Next, add #color(red)(5)# to each side of the inequality to isolate the #x# term while keeping the inequality balanced:

#11x - 5 + color(red)(5) > 72 + color(red)(5)#

#11x - 0 > 77#

#11x > 77#

Now, divide each side of the inequality by #color(red)(11)# to solve for #x# while keeping the inequality balanced:

#(11x)/color(red)(11) > 77/color(red)(11)#

#(color(red)(cancel(color(black)(11)))x)/cancel(color(red)(11)) > 7#

#x > 7#