How do you solve #4x - 5> x - 11#?

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Answer 1 · 2018-05-27T18:36:36

#x > 2#

#4x - 5 > x - 11#

Solving inequalities is similar to solving equations.

First, add #color(blue)5# to both sides of the inequality:
#4x - 5 quadcolor(blue)(+quad5) > x - 11 quadcolor(blue)(+quad5)#

#4x > x -6#

Now subtract #color(blue)x# from both sides of the inequality:
#4x quadcolor(blue)(-quadx) > x - 6 quadcolor(blue)(+quadx)#

#3x > 6#

Finally, divide both sides by #color(blue)3#:
#(3x)/color(blue)3 > 6/color(blue)3#

Therefore,
#x > 2#

This can also be said as "#x# is greater than #2#.

Hope this helps!