How do you solve #4x+6+3x=13#?

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Answer 1 · 2017-10-04T18:41:26

See a solution process below:

First, group and combine like terms on the left side of the equation:

#4x + 3x + 6 = 13#

#(4 + 3)x + 6 = 13#

#7x + 6 = 13#

Next, subtract #color(red)(6)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#7x + 6 - color(red)(6) = 13 - color(red)(6)#

#7x + 0 = 7#

#7x = 7#

Now, divide each side of the equation by #color(red)(7)# to solve for #x# while keeping the equation balanced:

#(7x)/color(red)(7) = 7/color(red)(7)#

#(color(red)(cancel(color(black)(7)))x)/cancel(color(red)(7)) = 1#

#x = 1#