How do you solve #-4x-8>16#?

1 Answer
Aug 6, 2015

Answer:

#x > -6#

Explanation:

#-4x -8 > 16#

adding 8 to both sides
#color(white)("XXXX")##rarr -4x > 24#

Either
[1] divide both sides by #(-4)#, remembering that multiplication or division by a negative reverses the inequality:
#color(white)("XXXX")##rarr x < -6#
or
[2] add #(4x-24)# to both sides
#color(white)("XXXX")##rarr -24 < 4x#
then divide by #4#
#color(white)("XXXX")##rarr -6 < x#