# How do you solve 4y^2-9=0 ?

Apr 13, 2018

$y = \pm \frac{3}{2}$

#### Explanation:

First let's add $9$ to each side

$4 {y}^{2} - 9 = 0$

$4 {y}^{2} = 9$

Now divide each side by $4$

${y}^{2} = \frac{9}{4}$

Now take the square root of each side

$\sqrt{{y}^{2}} = \sqrt{\frac{9}{4}}$

$y = \pm \frac{3}{2}$

$y = \pm \frac{3}{2}$