How do you solve #4y^2-9=0 #?

Question

3267 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-13T01:55:56

#y= pm3/2#

First let's add #9# to each side

#4y^2-9=0#

#4y^2=9#

Now divide each side by #4#

#y^2=9/4#

Now take the square root of each side

#sqrt(y^2)=sqrt(9/4)#

#y= pm3/2#

Answer

#y= pm3/2#