How do you solve #5< 1+ \frac { x } { 7}#?

1 Answer
Apr 13, 2017

See the entire solution process below:

Explanation:

First, subtract #color(red)(1)# from each side of the inequality to isolate the #x# term while keeping the inequality balanced:

#-color(red)(1) + 5 < -color(red)(1) + 1 + x/7#

#4 < 0 + x/7#

#4 < x/7#

Now, multiply each side of the inequality by #color(red)(7)# to solve for #x# while keeping the inequality balanced:

#color(red)(7) * 4 < color(red)(7) * x/7#

#28 < cancel(color(red)(7)) * x/color(red)(cancel(color(black)(7)))#

#28 < x#

To state the solution in terms of #x# we can reverse or "flip" the inequality:

#x > 28#