# How do you solve 5(2x+6)=-4(-5-2x)+3x?

Jul 27, 2018

$x = 10$

#### Explanation:

$5 \left(2 x + 6\right) = - 4 \left(- 5 - 2 x\right) + 3 x$

Use the distributive property to simplify/expand:
$10 x + 30 = 20 + 8 x + 3 x$

Simplify the right side:
$10 x + 30 = 20 + 11 x$

Subtract $\textcolor{b l u e}{11 x}$ from both sides:
$10 x + 30 \quad \textcolor{b l u e}{- \quad 11 x} = 20 + 11 x \quad \textcolor{b l u e}{- \quad 11 x}$

$- x + 30 = 20$

Subtract $\textcolor{b l u e}{30}$ from both sides:
$- x + 30 \quad \textcolor{b l u e}{- \quad 30} = 20 \quad \textcolor{b l u e}{- \quad 30}$

$- x = - 10$

Divide both sides by $\textcolor{b l u e}{- 1}$:
$\frac{- x}{\textcolor{b l u e}{- 1}} = \frac{- 10}{\textcolor{b l u e}{- 1}}$

Therefore,
$x = 10$

Hope this helps!

Aug 5, 2018

$x = 10$

#### Explanation:

We can distribute the $5$ on the left and the $- 4$ on the right to get

$10 x + 30 = 8 x + 20 + 3 x$

Next, we can combine the $x$ terms on the right to get

$10 x + 30 = 11 x + 20$

To make it easier, I'll switch the sides. I didn't do any math here, I just switched the sides:

$11 x + 20 = 10 x + 30$

We can subtract $10 x$ from both sides to get

$x + 20 = 30$

Lastly, to completely isolate $x$, let's subtract $20$ from both sides to get

$x = 10$

Hope this helps!