# How do you solve 5+3-2(6-:2)^3+|6-7|?

May 9, 2017

See a solution process below:

#### Explanation:

First, execute the operation within the Parenthesis and within the absolute value function:

$5 + 3 - 2 {\left(\textcolor{red}{6} \div \textcolor{red}{2}\right)}^{3} + \left\mid \textcolor{b l u e}{6} - \textcolor{b l u e}{7} \right\mid \implies 5 + 3 - 2 {\left(3\right)}^{3} + \left\mid - 1 \right\mid \implies$

$5 + 3 - 2 {\left(3\right)}^{3} + 1$

Next, execute the operation with the Exponent:

$5 + 3 - 2 \textcolor{red}{{\left(3\right)}^{3}} + 1 \implies 5 + 3 - 2 \times 27 + 1$

Then execute the Multiplication operation:

$5 + 3 - \textcolor{red}{2 \times 27} + 1 \implies 5 + 3 - 54 + 1$

Now, execute the addition and subtraction operations from left to right:

$\textcolor{red}{5 + 3} - 54 + 1 \implies 8 - 54 + 1$

$\textcolor{red}{8 - 54} + 1 \implies - 46 + 1$

$\textcolor{red}{- 46 + 1} \implies - 45$