# How do you solve 5-3c<=c+17?

Dec 19, 2016

$c \ge - 3$

#### Explanation:

Collect terms in c on one side of the inequality and numeric values on the other side.

$5 \cancel{- 3 c} \cancel{+ 3 c} \le c + 3 c + 17$

$\Rightarrow 5 \le 4 c + 17$

subtract 17 from both sides.

$5 - 17 \le 4 c \cancel{+ 17} \cancel{- 17}$

$\Rightarrow - 12 \le 4 c$

divide both sides by 4

$\frac{- 12}{4} \le \frac{\cancel{4} c}{\cancel{4}}$

$\Rightarrow - 3 \le c \text{ or } c \ge - 3$