How do you solve #5-3c<=c+17#?
1 Answer
Dec 19, 2016
Explanation:
Collect terms in c on one side of the inequality and numeric values on the other side.
add 3c to both sides.
#5cancel(-3c)cancel(+3c)<=c+3c+17#
#rArr5<=4c+17# subtract 17 from both sides.
#5-17<=4c cancel(+17)cancel(-17)#
#rArr-12<=4c# divide both sides by 4
#(-12)/4<=(cancel(4) c)/cancel(4)#
#rArr-3<=c" or " c>=-3#
