# How do you solve 5/6x-2x+4/3=5/3?

Nov 10, 2017

Look, in a way, 2 doesn't mean only 2, it also means $\frac{2}{1} , \frac{4}{2} , \frac{6}{3} , \frac{8}{4.} \ldots .$ till infinity
Looking in that way,
And also transferring $\frac{4}{3}$
$\frac{5 x - 12 x}{6} = \frac{5}{3} - \frac{4}{3}$
Solve
$\frac{- 7 x}{6} = \frac{1}{3}$
Transfer 6 to RHS to multiply $\frac{1}{3}$ by 6
$- 7 x = \frac{1}{\cancel{3}} ^ 1 \times {\cancel{6}}^{2}$
$- 7 x = 2$
Transfer -7 to RHS, to divide 2 by -7
$x = \frac{2}{-} 7$