How do you solve #5- 7m = 12- 2m#?

1 Answer
May 13, 2017

See a solution process below:

Explanation:

First, add #color(red)(7m)# and subtract #color(blue)(12)# from each side of the equation to isolate the #m# term while keeping the equation balanced:

#-color(blue)(12) + 5 - 7m + color(red)(7m) = - color(blue)(12) + 12 - 2m + color(red)(7m)#

#-7 - 0 = 0 + (-2 + color(red)(7))m#

#-7 = 5m#

Now, divide each side of the equation by #color(red)(5)# to solve for #m# while keeping the equation balanced:

#-7/color(red)(5) = (5m)/color(red)(5)#

#-7/5 = (color(red)(cancel(color(black)(5)))m)/cancel(color(red)(5))#

#-7/5 m#

#m = -7/5#