How do you solve #5+ 8x = 37#?

2 Answers
Apr 6, 2018

Answer:

The answer is #x = 4#.

Explanation:

First, you have to isolate the variable.

So subtract #5# on both sides.

#5 + 8x = 37# #-># #8x = 32#

And then divide by #8# on both sides

#8x = 32# #-># #x = 4#

Here's a link you can use if you still have trouble with the concept:
http://www.bbc.co.uk/bitesize/standard/maths_ii/algebra/solving_simple_equations/revision/1/

Apr 6, 2018

Answer:

#x = 4#

Explanation:

Let's see the problem again:

#5 + 8x = 37#

First, you subtract 5 from 5, after, you subtract 5 from 37.
Now our problem should look like this:

#8x = 32#

Now, you divide #8x# and #32# both by 8.
8x divided by 8, the two 8's eliminate each other, so for the 8, you are left with just:

#x#

Now, lastly, you divide 32 by 8, which is 4. You are left with:

#color(red)(x = 4#

Hope this helps! :)