# How do you solve -5< \frac{8x - 5}{6} < 7?

Jun 5, 2018

Undo the operations surrounding $x$ by applying the inverses to both sides in the reverse order.

#### Explanation:

Multiply all sides by $6$:

$- 30 < 8 x - 5 < 42$

Add $5$:

$- 25 < 8 x < 47$

Divide all sides by $8$:

$- \frac{25}{8} < x < \frac{47}{8}$